1. Nikhil is 15 years elder to Krishna. If 5 years ago, Nikhil was 3 times as old as Krishna, then find Nikhil’s present age.
A. 32.5 years
B. 27.5 years
C. 25 years
D. 24.9 years

Explanation:
let Nikhil's age be N
Let Krishna's age be K
N=K+15
(N-5)=3*(K-5)
K=12.5,N=27.5
N=27.5

2. Ten years ago, Deepika was half of Shambhavi's age. If the ratio of their present ages is 3 : 4 , what will be the total of their present ages?
A. 45
B. 30
C. 35
D. 40

Explanation:
Let present age of Deepika be D
Let present age of Shambhavi be S
D=S/2
(D-10)=(Q-10)/2
D=15, S=20

D+S=35

3.Sana is aged three times more than her daughter Impana. After 8 years, she would be two and a half times of Impana's age. After further 8 years, how many times would she be of Impana's age?
A. 5 times
B. 4 times
C. 3 times
D. 2 times

Explanation:
let Sana's age be S
Let Impana's age be I
S=3I+I =4I
(S+8)=5/2*(I+8)
S=32 ,I=8

S+8+8=48

I+8+8=24

48/24=2

4. Vrushabh's age is 125 % of what it was 10 years ago, but 250/3 % of what it will be after 10 years. What is his present age?
A. 40
B. 70
C. 50
D. 60

Explanation:
Let Vrushabh's age be V
V=125/100*(M-10)

M=50

5. Trisha is 24 years older than Megha. In two years, her age will be twice the age of Megha. What is the present age of megha?
A. 23 years
B. 22 years
C. 21 years
D. 20 years

Explanation:
Let Trisha's age be T
Let Megha's age be M
T=24+M
T+2=(M+2)*2

M=22

6. Present ages of Shishira and Vinay are in the ratio 5 : 4 . Three years hence, the ratio of their ages will become 11 : 9 . What is Vinay's present age in years?
A. 24
B. 22
C. 26
D. 28

Explanation:
let shishira's age be S
Let Vinay's age be V
S/V=5/4
S+3/V+3=11/9

V=24

7. Ten years ago, the age of Gayatri was three times the age of Manasa. After ten years, Gayatri's age will be twice that of Manasa. Find the ratio of their present ages.
A. 11 : 7
B. 9 : 5
C. 7 : 4
D. 7 : 3

Explanation:
let Gayatri's present age be G
Let Manasa's present age be M
(G-10)=3(M-10)
(G+10)=2(M-10)
M=30,G=70

G/M=7:3

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